[Wikitex-l] Re: SELinux/web2c LaTeX permissions issues in WikiTeX <amsmath> (Peter Danenberg)

[Lengyel, Florian]

Hi, I'm replying for Mike Carlisle.

The command: 
[mathwiki at cml wikitex]$ ./wikitex.sh amstest amsmath /extensions/wikitex/tmp
[mathwiki at cml wikitex]$
Seems to do absolutely nothing!

FL

Message: 1
Date: Wed, 25 Jan 2006 18:50:49 -0500
From: Michael Carlisle <mcarlisle at gc.cuny.edu>
Subject: [Wikitex-l] [Fwd: Error messages] SELinux/web2c LaTeX
	permissions issues in WikiTeX <amsmath>

Trying to get WikiTeX to run under Red Hat/SELinux using web2c's 
implementation of LaTeX gave the errors below (sorry for the length).  
Does someone understand the permissions issues we're having here?  (I've 
offset the errors for easier viewing... at the top and bottom.)  Is this 
even a WikiTeX permissions issue, or does it look like a deeper LaTeX 
permissions issue?

Thanks in advance for your help!

Mike Carlisle
Mathematics Dept.
CUNY Graduate Center

[ snip ]

Message: 2
Date: Wed, 25 Jan 2006 17:54:28 -0600
From: Peter Danenberg <pcd at wikitex.org>
Subject: Re: [Wikitex-l] [Fwd: Error messages] SELinux/web2c LaTeX
	permissions	issues in WikiTeX <amsmath>
To: WikiTeX General <wikitex-l at wikitex.org>
Message-ID: <20060125235428.GB9139 at wikitex.org>
Content-Type: text/plain; charset="us-ascii"

> Is this even a WikiTeX permissions issue, or does it look like a
> deeper LaTeX permissions issue?


     Would  you  mind,  Mike,  saving  the  attached file as
extensions/wikitex/tmp/amstest, and manually invoking:

     ./wikitex.sh amstest amsmath /extensions/wikitex/tmp/

from extensions/wikitex?

--
Peter Danenberg                                           .
wikisophia.org                                           ..:
-------------- next part --------------
\documentclass[12pt]{article}
\usepackage{amssymb,amsmath,amscd,concmath}
\pagestyle{empty}
\begin{document}
\begin{equation*}
\label{e:barwq}\begin{split}
H_c&=\frac{1}{2n} \sum^n_{l=0}(-1)^{l}(n-{l})^{p-2}
\sum_{l _1+\dots+ l _p=l}\prod^p_{i=1} \binom{n_i}{l _i}\\
&\quad\cdot[(n-l )-(n_i-l _i)]^{n_i-l _i}\cdot
\Bigl[(n-l )^2-\sum^p_{j=1}(n_i-l _i)^2\Bigr].
\end{split}
\end{equation*}
\end{document}

------------------------------

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Michael Carlisle
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